0=a^2+4a+5

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Solution for 0=a^2+4a+5 equation:



0=a^2+4a+5
We move all terms to the left:
0-(a^2+4a+5)=0
We add all the numbers together, and all the variables
-(a^2+4a+5)=0
We get rid of parentheses
-a^2-4a-5=0
We add all the numbers together, and all the variables
-1a^2-4a-5=0
a = -1; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·(-1)·(-5)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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